Draw an Octagon using Python's Turtle Module (Computer Programming Language) - Code Sheet

 Hi, 

I am sharing the code sheet in Python language that you can copy and paste, as it is, onto the interfaces such as Pycharm and Intellij to get the Octagon in yellow colour. If you have any doubts, please let me know in the comment box.

import turtle
sanju = turtle.Turtle()
sanju.color("red", "yellow")
sanju.begin_fill()
sanju.forward(100)
sanju.left(45)
sanju.forward(100)
sanju.left(45)
sanju.forward(100)
sanju.left(45)
sanju.forward(100)
sanju.left(45)
sanju.forward(100)
sanju.left(45)
sanju.forward(100)
sanju.left(45)
sanju.forward(100)
sanju.left(45)
sanju.forward(100)
sanju.left(45)
sanju.end_fill()
turtle.done()

Solved Example-Distance of a Point from a Line, whose end Co-ordinates are given.

Hi,

Problem:
The X and Y coordinates(in meters) of station Shore are 246.87 and 659.46 respectively, and those for station Rock are 437.85 and 973.48, respectively. The azimuth, bearing, and length of the line connecting station Shore to station Rock are 31d,18 m, 24 s,  N31 d18 m 24s E, and 367.540 m, respectively.
What is the perpendicular distance of a point from the line if the X and Y coordinates of the point are 414.278 and 959.083, respectively?

Note:




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Let me know if you have any doubts about the solution, I will make it easy for you.

solved Example - Find the elevations at full and half stations along sag curve

Problem:
A -2.8% grade line meets a +3.6% grade line at station 125+00.  Elevation=1631.04 ft. Determine the elevation of all full and half stations if a 650-ft curve is to be used.

solution:

Solution of vertical curve length, that passes through a fixed point elevation - solved example.

Problem:
A -4% downgrade intersects a +3% upgrade at elevation 120.00 ft at station 95 + 00. it is desired to pass a vertical curve through a point of elevation 128.00 ft at station 96 + 00. determine the curve length required.

solution:

Solved - Vertical parabolic curve - PVI, PVC and PVT and Elevations at different stations along Curve

Hi, 

Here is the example which shows you how to solve for the vertical transition curve elevation.

Problem: A 3% grade intersects a -2% grade at station 4+350m with an elevation of 190.5m. Given that a 250m symmetrical parabolic curve highway is utilized, determine:

elevation in meters at station 4+240
elevation in meters at station 4+260
elevation in meters at station 4+280
elevation in meters at station 4+300

Vertical Parabolic curve - PVI, PVC and PVT

Solution: Please refer the images below.

Parabolic vertical curve - elevation at stations along curve

thanks!

Curves - Degree (Chord and Arc Definition) - L,T,E,M,Lc,PT,, PC

Hi,
If you are given with the degree, angle of intersection and Station of PI, how to find the L(length of curve), T(Tangent length), E(External ordinate), M, Lc(Length of chord), PT(Point of tangency) station, PC(Point of Curvature) station. The formulae and example is given in the following images.

Example has three parts, each part is a different question in itself.





Thanks!


       

How to Draw Contours using Judgement and Free Hand Method

Hi,

There are other method of contouring like the arithmetic estimation, but for less accurate but quick draw, one can use their fine judgement and free hand technique to draw the contours for the given elevation points. 

In the following example, the control points are already drawn. The square patterned control points' elevations are shown, one has to use the fine judgement to draw the contour lines. See how it is done, all you have to do is to judge the contour line's placement from the given elevations. 



       

Look at the nearest control point elevations. If the nearby elevation is higher, then the terrain is rising towards it, if it is lower, terrain must have a downward gradient. 

Definitely the higher contour must lie towards the rising terrain and a contour with the lower elevation must lie towards the downward gradient. 

Drawing Contour Lines free hand with fine judgement

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